### Intersects of 2 functions

Assuming function $f$ and $g$, `scipy.optimize.fsolve`

would give an elegant solution:

```
from scipy.optimize import fsolve
def f(xy):
x, y = xy
return (y - x ** 2, y - np.sin(x))
fsolve(f, [1.0, 1.0])
```

gives `array([0.87672622, 0.76864886])`

is the intersect of $y=x^2$ and $y=\sin(x)$.

### Intersects of 2 arrays

There is a function called `numpy.intersect1d`

that returns the sorted, uniq values in both arrays, and `reduce(np.intersect1d, list_of_arrays)`

gives intersect of all arrays in the list. Index can also be returned by `return_indices=True`

option.

If the 2 arrays are data values, using `np.flatnonzero(np.abs(arr1-arr2))<tol)`

seems to be a good solution; this method returns the indices of values in `arr1`

and `arr2`

which are closed by `tol`

.

Another method is based on idea that there is a change in sign of $\lim_{x\to x_0^+}f(x_0)-g(x_0)$ and $\lim_{x\to x_0^-}f(x_0)-g(x_0)$, therefore, if $\mathrm{d}x$ is small enough, this method would give a very good estimation of the intersects.

```
def intersects(x, arr1, arr2):
return x[np.flatnonzero(np.diff(np.sign(arr1 - arr2))]
```

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